Mike and Rich are confusing me.

I do have my own understanding. I hope it is correct and this is what it is....
You can pretty easily calculate the wheel torque (Mike's force at wheel) for a given RPM if you know the engine torque at that RPM (which is why you need the dyno print out). With the vehical weight and the wheel torque values for a given RPM, you can calculate the instantanous acceleration value. Which as Rich (and those online resources say) will show that you will get max acceleration at max torque. Now the actual max value will be different on a per gear basis, but will happen at the same RPM.
I can then take the speed and wheel torque (for a given RPM and gear) and place that on a graph. Vary the RPM for that one gear and you should have a graph for that given gear. Do that for all gears. Then overlay those graphs. I think that IF for example your second gear graph drops lower than your third gear graph at some point in your available RPM range, this intersection would mean that your wheel torque is the same in both gears for a given speed (MPH). That means as your 2nd gear wheel torque continues to drop, your 3rd gear wheel torque is probably climbing. That is your shift point. The question is, will this happen before redline in the lower gear?
In my car 1st to 2nd doesn't intersect and 2nd to 3rd don't intersect. So this means run it up to redline and then shift. Each shift will give me a drop in wheel torque as the previous gear is always giving me more wheel torque across the entire RPM range. 3rd to 4th and 4th to 5th both touch, but just right at about redline. This means again that I will still shift at redline, but when I shift from 3rd to 4th and 4th to 5th, the acceleration should feel pretty much unchanged (wheel torque is about the same) while the 1st to 2nd and 2nd to 3rd upshifts will have a noticable drop in acceleration each time the gear changes as the wheel torque for the higher gear is lower when I shift.
I found this image on corner carvers interesting....
...which shows that if you care about wheel torque (or force), that this shows how a high RPM low torque engine can equal a low RPM high torque engine. This done via gearing. So RPM ( or HP

) is what does it.
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Richard Casto
1972 Porsche 914
2013 Honda Fit Sport
2015 Honda Fit EX
http://motorsport.zyyz.comMoney can't buy happiness, but somehow it's more comfortable to cry in a Porsche than a Kia.